4t^2-6t-8=-10

Solution for 4t^2-6t-8=-10 equation:

4t^2-6t-8=-10

We move all terms to the left:

4t^2-6t-8-(-10)=0

We add all the numbers together, and all the variables

4t^2-6t+2=0

a = 4; b = -6; c = +2;
Δ = b2-4ac
Δ = -62-4·4·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*4}=\frac{4}{8}
=1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*4}=\frac{8}{8}
=1
$